Rank Calculation of JEE Main 2019; Know How it is Done?

The result for JEE Main January session is already released. For April session, the result will be declared on 30 April. The candidates will be able to know their scores by logging in to the official website of JEE via their Application number and date of birth as their password. Now, the biggest question arises is that how to calculate JEE Main rank based on the JEE Main Result. The final rank for the exam will be declared on the basis of marks of the candidate who appeared in JEE main. If a student has appeared in both, January and April session then the better scores will be considered for the declaration of rank.

NTA has announced that the normalisation of marks will be done session wise so that the percentile score is relative to the percentile scores of others. The concept of percentile is different from the percentage. For example, the percentile score denotes the percentage of candidates who have scored equal or less than the percentile in the examination. So, to know your rank by calculating your percentile is a bit tricky task but we have made it easy for you to estimate your percentile through your JEE Main result and know your probable rank.

How to Calculate Your Rank?

To know your rank, you should know the total number of candidates that appeared in the exam. According to NTA, in January session, 8, 74,469 students appeared and out of those, 15 students have scored 100 percentile.

To calculate the JEE Main 2019 rank, you first need to know the percentage of people who are ahead you and who have a higher percentile score than yours. Since the percentile score is calculated on a scale ranging from 100 to 0 for each session of examinees, the formula applies that the total number of students appeared in the January session which is 874469 /100 and then multiplied it by the percentage of people who are ahead of you to arrive at the rank. So, here is the formula to calculate you JEE Main rank 2019.

JEE Main 2019 rank = (100- NTA percentile score) X 874469 /100

Let's say your percentile score is 90.70; JEE Main rank will be (100-90.70) X 874469/100 = 81325. Let us take another example, where the NTA score is 80.60 then JEE Main 2019 rank = (100-80.60) X 874469 /100. The rank will be 169646.

While calculating your rank, make sure that you use the formula right to make your calculation precise. Also, the rank that you will get on your own will not be accurate but will be a probable rank. It will give you an idea of where you stand and likewise, you can apply for colleges that you think are suitable.

Students who have appeared for the January session and still waiting for the April session should go for it if they are not satisfied with their score received in January session. The scorecard for the students who appear in both the session will be declared on April 30, and then their final rank will be displayed based on the paper in which they have a better JEE Main score.

Minimum Percentile Required to be Eligible for JEE Advanced

As per the sources of various teachers and coaching professionals it is considered that a score of 85 in the JEE Main exam will stand a chance to be eligible for JEE Advanced. Although there is no written notice regarding this from the NTA, it is just an assumption. Students are very eager to know about the minimum cut off for JEE Main 2019, but until April 30 nothing can be said about it. Students will have to wait to know the minimum cut off to qualify for JEE Advanced 2019.

JEE is indeed one of the biggest dreams for every engineering aspirant, but only a few get into the IITs and NITs. However, many students find other good colleges and do well in life. The JEE Main result for January session was exceptionally well, and the same is expected from the upcoming April session. There are good and fair chances that more numbers of students may qualify for Advance this year. Therefore, you must start preparing to stand out your chance to be called as an IITian.